A. What impulse must be imparted to a golf ball of mass 0.043 kg to give it a velocity of 48.8 m/s? I think the answer is 2.09 kg m/s but im really confused on this next part B
B. If the golf club is in contact with the ball as it is accelerated over an interval of 1.11 cm, estimate the average force exerted on the ball by the club.Physics - finding the average force exerted on a golf ball when hit with a club?A) Impulse (I) = delta P = m x delta v = 0.043 x 48.8 = 2.09 N-s
B) By v^2 = u^2 + 2as
=%26gt;(48.8)^2 = 0 + 2 x a x (1.11 x 10^-2)
=%26gt;a = 214544.14 m/s^2
Thus By F = ma
=%26gt;F = 0.043 x 214544.14 = 9225.40 N
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment