What is the spring constant of the golf ball?

What is a good estimate for the spring constant of the golf ball (assuming that it behaves like a Hooke's Law spring under compression)?What is the spring constant of the golf ball?I am taking a Physics and we just did a lab on Hooke's Law.

Spring Constant- springs resistance to being stretched, it tells us the stiffness. The larger the spring constant the larger the force which makes it harder to stretch. Hooke's Law is basically explaining the behavior of spring, the more you stretch or compress is, more force is required. The formula for calculating the force due to a spring is:



F=kx

meanings:

F (force of the spring)

k (spring constant measured in N/m or N/cm) which is Newton Meters or Centimeters

x (distance stretched)



Force of the spring is equal to the weight

(Newton's 2nd Law)



I'm not sure if this really answers your question but I hope it helps and leads you in the right direction. Best of luck.What is the spring constant of the golf ball?well... my best answer for this question would be to think of the "spring constant" as gravity. The reason i say gravity is because if you were to drop a golf ball from a certain height, it would of course, bounce. But the height of the bounce would not be as high as the original height at which the ball was dropped. So this also proves true in the case of a spring with a certain spring constant. When you have a spring and block attached to the end, when the system is oscillating, the spring will not go to the original point at which the spring was pulled... Dropping a golf ball and witnessing the bounces is much easier to see than the difference in oscillations of a block and spring.



I hope i was able to answer your question... or at least give you another way to look at it...